Consider a logical address space of 8 pages of
1024 words mapped with memory of 32
frames.
How many bits are there in the physical
address ?
(A) 9 bits
(B) 11 bits
(C) 13 bits
(D) 15 bits
size of logical address space is No. of pages *Page size = 8 * 1024 = 2^3 * 2 ^10 = 2^13
No. of bits for logical address is 13
Size of Physical address space is 2^5(32) * 2^10 (1024)=
2^15 No. of bits for physical address is 15
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